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-2=2(-2)^2-3x+8
We move all terms to the left:
-2-(2(-2)^2-3x+8)=0
We calculate terms in parentheses: -(2(-2)^2-3x+8), so:We get rid of parentheses
2(-2)^2-3x+8
determiningTheFunctionDomain -3x+8+2(-2)^2
We add all the numbers together, and all the variables
-3x+16
Back to the equation:
-(-3x+16)
3x-16-2=0
We add all the numbers together, and all the variables
3x-18=0
We move all terms containing x to the left, all other terms to the right
3x=18
x=18/3
x=6
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